If the equilibrium concentration of CO is 3.4 × 10–1 M, and the equilibrium concentration

of H2 is 6.8 × 10–1 M, the equilibrium concentration of CH3OH is ?

4.1M = [CH₃OH]

Explanation:

The equilibrium produced for the reaction between CO and H₂ to form CH₃OH is:

CO + 2 H₂ ⇄ CH₃OH

Where Keq is defined as:

Keq = 26 = [CH₃OH] / [CO] [H₂]²

For concentrations in equilibrium

Replacing in Keq the equilibrium concentrations of CO and H₂, the equilibrium concentration of CH₃COOH is:

26 = [CH₃OH] / [3.4x10⁻¹M] [6.8x10⁻¹M]²

4.1M = [CH₃OH]

the first one is B.) At equilibrium the products are favored

the second one A.) 4.1M