The solid-state transition of sn(gray) to sn(white) is in equilibrium at 18.0 ˚c and 1.00 atm, with an entropy change of 8.8 j k-1 mol-1. the density of gray tin is 5.75 g cm-3; that of white tin is 7.28 g cm-3. calculate the transition temperature at a pressure of 100.0 atm.

Transition temperature = 13 C

Explanation:

ΔS(transition) = 8.8 J/K.mol

ρ(gray) = 5.75 g/cm³ = 5750 kg/m³

ρ(white) = 7.28 g/cm³ = 7280 kg/m³

ΔP = 100 atm = 100 x 101325 = 10132500 Pa

M(Sn) = 118.71g/mol = 118.71 x 10⁻³ kg/mol

T(i) = 18 C, T(f) = ?

We know that

G = H - TS, where G is the gibbs free energy, H is the enthalpy, T is the temperature and S is the entropy

H = V(m) x P, hence the equation becomes

G = V(m) x P - TS

The change in Gibbs free energy going from G(gray) to G(white) = 0 as no change of state takes place hence it can be said that

ΔG(gray) - ΔG(white) = 0

replacing the G with it formula shown above we can arrange the equation such as

0 = V(m)(gray) - V(m)(white) x ΔP - (ΔS(gray) - ΔS(white)) x ΔT

solving for  ΔT we get

ΔT = {V(m)(gray) - V(m)(white) x ΔP}/(ΔS(gray) - ΔS(white))

ΔT = {M(Sn)(1/ρ(gray) - 1/ρ(white) x ΔP}/(ΔS(gray) - ΔS(white))

ΔT = {118.71 x 10⁻³ x {(1/5750) - (1/7280)} x 10132500}/(8.8)) = 5.0 C

ΔT = T(initial) - T(transition)

T(transition) = T(initial) - ΔT = 18 - 5 = 13 C

1.consider the following balanced equation and answer parts a through. show calculations for each part.  

3 ag(s) + 4 hno3(aq) → 3 agno3(aq) + no(g) + 2 h2o(l)  

a. calculate the number of moles of agno3 produced by the reaction of 3 moles of ag with excess hno3. if the number to the left of the compound represents the number of moles of the compound which are present, then 3 moles of ag react with 4 moles hno3 to produce 3 moles agno3 (aq).

so the answer to a would be 3 moles.

b. calculate the number of moles of agno3 produced by the reaction of 108 grams of ag with excess hno3.  

i'm not sure how to plug in the grams of silver into an equation using moles to find how many moles are produced.

c. calculate the number of grams of agno3 produced by the reaction of 108 grams of ag with excess hno3  

d. calculate the number of moles of no produced as a byproduct of the reaction of 108 grams of ag with excess hno3.  

e. calculate the number of grams of no produced as a byproduct starting with 108 grams of ag and excess hno3.  

explanation:

the correct answer is option d

explanation:

i was wrong its d because they dont use cm when calculating square roots