a 125 kg wrecking ball on a 15.4 m long cable is pulled back to an angle of 33.5 degrees and released. How much KE does it have at the bottom of its swing? (Unit = J)

mgh = mv2/2; h = l(1 - cos33.5°); v = [2gl(1 - cos33.5°)]1/2 = 8 m/s.

We esed law of conservation of enrtgy.

Explanation:

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explanation:

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