Consider the following unbalanced equation: agno3 (aq) cacl2 (aq) → agcl (s) ca(no3)2 (aq) how many grams of silver chloride can be prepared by the reaction of 100.0 ml of 0.20 m silver nitrate with 100.0 ml of 0.15 m calcium chloride?

3 grams

Explanation:-

To calculate the number of moles for given molarity, we use the equation:

    .....(1)

Molarity of solution = 0.20 M

Volume of solution = 100.0 mL = 0.1 L

Putting values in equation 1, we get:

Molarity of solution = 0.15 M

Volume of solution = 100.0 mL = 0.1 L

Putting values in equation 1, we get:

The balanced chemical equation for the reaction is:

According to stoichiometry :

2 moles of require 1 mole of

Thus 0.02 moles of will require=  of

Thus is the limiting reagent as it limits the formation of product and is the excess reagent.

As 2 mole of give = 2 mole of

Thus 0.02 moles of give =  of

Mass of

Thus 3 g of will be produced from the given masses of both reactants.

wher is the rest of the question