Aqueous hydrobromic acid hbr reacts with solid sodium hydroxide naoh to produce aqueous sodium bromide nabr and liquid water h2o . if 0.555g of sodium bromide is produced from the reaction of of 2.4g hydrobromic acid and 0.77g of sodium hydroxide, calculate the percent yield of sodium bromide.

28 %

Explanation:

First we have to calculate the moles of

Now we have to calculate the moles of

The balanced chemical reaction will be,

From the balanced reaction, we conclude that

As, 1 mole of react with 1 mole of

So, 0.019 moles of react with= mole of

Thus acts as the limiting reagent as it limits the formation of product and [tex}HBr[/tex] is the excess reagent.

As, 1 mole of give= 1 mole of

So, 0.019 moles of react with= mole of

Now we have to calculate the mass of

Now we have to calculate the percent yield of

Therefore, the percent yield of sodium bromide is 28%

it is the most commonly accepted one

the correct answer to this question is 2