A24.00 ml sample of a solution of pb(clo3)2 was diluted with water to 52.00 ml. a 17.00 ml sample of the dilute solution was found to contain 0.220 m clo3−(aq). what was the concentration of pb(clo3)2 in the original undiluted solution? 3.60 × 10−2 m 7.19 × 10−2 m 0.238 m 0.156 m 0.477 m

0.238 M

Explanation:

A 17.00 mL sample of the dilute solution was found to contain 0.220 M ClO₃⁻(aq). The concentration is an intensive property, so the concentration in the 52.00 mL is also 0.220 M ClO₃⁻(aq). We can find the initial concentration of ClO₃⁻ using the dilution rule.

C₁.V₁ = C₂.V₂

C₁ × 24.00 mL = 0.220 M × 52.00 mL

C₁ = 0.477 M

The concentration of Pb(ClO₃)₂ is:

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explanation:

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