Predict the effect of a large amount of acetyl-coa on the activity of pyruvate dehydrogenase and the rate of glycolysis. note: pyruvate dehydrogenase is the enzyme that catalyzes the formation of acetyl-coa from pyruvate. a. pyruvate dehydrogenase activity will decrease while the rate of glycolysis will increase. b. both pyruvate dehydrogenase activity and the rate of glycolysis will decrease. c. pyruvate dehydrogenase activity will increase while the rate of glycolysis will decrease. d. the rate of glycolysis will increase, thereby, leading to an increase in pyruvate dehydrogenase activity.

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

it's all four options.

you gotta add the following molecules so we can give u an answer

explanation: