Use the following to calculate h°lattice of mgf2. mg(s) mg(g) h° = 148 kj f2(g) 2 f(g) h° = 159 kj mg(g) mg+(g) + e- h° = 738 kj mg+(g) mg+2(g) + e- h° = 1450 kj f(g) + e- f -(g) h° = -328 kj mg(s) + f2(g) mgf2(s) h° = -1123 kj kj/mol

The correct answer is -2952 KJ/mol

Explanation:

Attached is the diagram for Born- Haber cycle. According to the cycle:

ΔHf= ΔH1 + ΔH2 +  ΔH3 + ΔH4 + ΔH5 + LE

In order to calculate the lattice energy (LE):

LE= ΔHf - ΔH1 - ΔH2 -  ΔH3 - ΔH4 - ΔH5

LE= -1123 KJ/mol - 148 KJ/mol -  159 KJ/mol - 728 KJ/mol - 1450 KJ/mol - (2 x (-328 KJ/mol)

LE= -2952 KJ/mol

the answer is learned