write the nuclear equation for the alpha decay of:
(a) ra-256

(b) rn - 219

(c) po - 211

(d) pb-210

(e) u-238

The answer to your question is below

Explanation:

Alpha decay occurs when a radioactive atm emits an alpha particle (Helium atom).

a)      ²⁵⁶Ra      ⇒      ²⁵²₈₄ Po  +   ⁴₂He

b)     ²¹⁹Rn       ⇒      ²¹⁵₈₂Pb    +   ⁴₂He

c)      ²¹¹Po      ⇒      ²⁰⁷₈₀Hg    +   ⁴₂Hg

d)      ²¹⁰Pb     ⇒     ²⁰⁶₇₈Pt      +   ⁴₂Hg

e)      ²³⁸U      ⇒     ²³⁴₈₈U       +   ⁴₂Hg

b is the correct answer

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