Chemistry, 19.11.2019 22:31 hwest98

Water’s specific heat capacity is 4.186 joules/gram degree celsius. mercury’s specific heat capacity is 0.140 joules/gram degree celsius.

water and mercury are put into three identical bowls:

bowl a contains 20 grams of water.

bowl b contains 40 grams of water.

bowl c contains 20 grams of mercury.

the bowls start at the same temperature, and then the same amount of heat is added to each bowl. order the bowls from coolest to warmest, based on their final temperatures.

bowl a

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Answer from: loroloco71

The order of bowls from coolest to warmest based on their final temperatures will be:

Bowl B < Bowl A < Bowl C

Explanation:

Same amount of heat is added to each bowl = Q

Bowl -A:

Mass of the water ,m= 20 g

Initial temperature of the water = T_1

Final temperature of the water = T_2

Heat capacity of the water= c = 4.186 J/g°C

Change in temperature of the water = $\Delta T_1=(T_2-T_1)$

$Q=mc\times \Delta T_1=mc\times (T_2-T_1)$

$Q=20 g\times 4.186 J/g^oC\times \Delta T_1$

$\Delta T_1=\frac{Q}{m\times c}$

$\Delta T_1=\frac{Q}{20 g\times 4.186 J/g^oC}$ ..[1]

Bowl -B:

Mass of the water ,m' = 40 g

Initial temperature of the water = T_1

Final temperature of the water = T_3

Heat capacity of the water= c = 4.186 J/g°C

Change in temperature of the water = $\Delta T_2=(T_3-T_1)$

$Q=m'c\Delta T_2=mc\times (T_3-T_1)$

$Q=40 g\times 4.186 J/g^oC\times \Delta T_2$

$\Delta T_2=\frac{Q}{m'\times c}$

$\Delta T_2=\frac{Q}{40 g\times 4.186 J/g^oC}$ ..[2]

Bowl -C:

Mass of the mercury ,m''= 20 g

Initial temperature of the mercury = T_1

Final temperature of the mercury = T_4

Heat capacity of the mercury= c' = 0.140 J/g°C

Change in temperature of the water = $\Delta T_3=(T_4-T_1)$

$Q=m''c'\Delta T_3=mc\times (T_4-T_1)$

$Q=20 g\times 4.186 J/g^oC \times \Delta T_3$

$\Delta T_3=\frac{Q}{m''\times c'}$

$\Delta T_3=\frac{Q}{20 g\times 0.140J/g^oC}$ ..[3]

Taking ratio of [1] , [2],and [3]

$\Delta T_1 :\Delta T_2 :\Delta T_3$

= $\frac{Q}{20 g\times 4.186 J/g^oC}:\frac{Q}{40 g\times 4.186 J/g^oC}:\frac{Q}{20 g\times 0.140J/g^oC}$

$\Delta T_1 :\Delta T_2 :\Delta T_3$ = 1 : 0.5 : 29.9

As substance with larger value in change in temperature will have higher temperature on addition of energy. So, the order of bowls from coolest to warmest based on their final temperatures will be:

Bowl B < Bowl A < Bowl C

Answer from: Quest

explanation:

venn diagram is pictorial representation with of circles showing the relation between two finite sets or things. the intersection part of two circles conveys the relation present in between those sets or things.

here in the venn diagram of sand and salt two circles represent sand and salt. but the area falling under the intersection of these circle represents the mixture of sand and salt.

so, in a venn diagram the mixture will be placed in a middle that is in between the intersection of two circles.

Answer from: Quest

The answer to your question really depends on three things: how much water you have, how cold it is to start out, and how cold the things around it are. water actually freezes when it gets to 32 degrees fahrenheit (0 degrees celsius), but the time it takes to get there may be different. let's start with the first. if you take two glasses, and fill one with a tiny bit of water, and the other about halfway, then put them both in the freezer, the one with less water will freeze first (you can try this at home, but i recommend using plastic cups and not glass ones). now let's move on to the second part. let's say you have two glasses, and you fill one with really cold water that has been in the refrigerator, and the other with really hot water from the sink. if you put both of them in the freezer, the one that started out colder will freeze first. for the third part, let's imagine that you have two glasses with the same amount of water in them, and the water is at the same temperature. imagine putting one outside on a really really cold day in georgia, and having a friend in alaska put one outside on the same day. since it would be so much colder in alaska, the glass of water there would freeze before yours. so, if you took a tiny bit of really cold water in a glass, and put it outside on a cold day in alaska, it would freeze a lot faster than a big glass of hot water outside on a cold day in georgia.

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