The following equation, derived from newton's version of kepler's third law, allows us to calculate the mass (m) of a central object, in solar masses, from an orbiting object's period (p) in years and semimajor axis (a) in astronomical units: m=a3p2 using this formula with the values you found in parts c and d, what is the approximate mass of the central object? view available hint(s)

what are the two models

explanation:

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole