Electric power is measured in watts (1 w = 1 j/s). about 95% of the power output of an incandescent bulb is converted to heat and 5% to light. if 12% of that light shines on your chemistry textbook, how many photons per second shine on the book from a 62 w bulb? (assume that the photons have a wavelength of 504 nm). enter a number in scientific notation (e. g. 1.23e12).

9.430 * 10¹⁷ protons per second whill shine on the book from a 62 W bulb

Explanation:

To answer this question, first let's calculate the energy of a single photon with a wavelength (λ) of 504 nm:

E = hc/λ

Where h is Planck's constant (6.626*10⁻³⁴ J·s) and c is the speed of light (3*10⁸ m/s).

E = 6.626*10⁻³⁴ J·s * 3*10⁸ m/s ÷ (504*10⁻⁹m) = 3.944 * 10⁻¹⁹ J.

So now we can make the equivalency for this problem, that

1 proton =  3.944 * 10⁻¹⁹ J

Now we convert watts from J/s to proton/s:

1 = 1 W

Solving the problem, a 62 W bulb converts 5% of its output into light, so:

3.1 watts are equal to [ 2.535*10¹⁸ proton/s * 3.1 ] = 7.858 * 10¹⁸ proton/s

Of those protons per second, 12% will shine on the chemistry textbook, thus:

7.858 * 10¹⁸ proton/s * 12/100 = 9.430 * 10¹⁷ protons/s

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.

the maximum mass of nh3 is nh3 in grams