In standard (x, y) corrdinate plane, what is the slope of the line given by the equation 4x=7y+5?

To find the answer, you need to put that equation in standard form. The first step is to isolate y. To do that, you need to subtract 5 from both sides. It would cancel 5 from the right side of the equation while the left side would now be: 4x - 5. Next, you need to divide 7 from both sides to isolate 7. Your equation should now look like this: 4x - 5 / 7 = y. To bring it altogether: y = 4/7x - 5/7

The question is asking for the slope of the line and that would be 4/7x.

D.

Xis -1/2
y is 35/4.