H2(g)+cl2→2hcl(g)

how many liters of hcl are produced when 28 l of chlorine are reacted with excess hydrogen?

(one mole of any gas occupies 22.4 l under certain conditions of temperature and pressure. assume those conditions for this question.)

22.4 l

56 l

112 l

224 l

56 L of HCl

The equation for the reaction is;

H₂(g )+ Cl₂(g) →2HCl(g)

Volume of Chlorine gas = 28 L

According to the question, 1 mole of a gas occupies 22.4 L at stp.

We are required to determine the volume of HCl produced.

Volume of Chlorine gas = 28 L

But;

1 mole = 22.4 L

Therefore;

Moles of Chlorine gas = 28 L ÷ 22.4 L

                                    = 1.25 moles of Cl₂

From the equation 1 mole of Cl₂ reacts with hydrogen gas to produce 2 moles of HCl

Therefore, the mole ratio of Cl₂ to HCl is 1: 2

Thus; moles of HCl = 1.25 × 2

                                = 2.5 moles

We know that. 1 mole of a gas = 22.4 L

Thus,

The volume of HCl = 2.5 moles × 22.4 L/mol

                                =56 L of HCl

Therefore, 56 L of HCl are produced when 28 L of chlorine gas reacts with excess hydrogen gas.

both adhesion and cohesion are attractions.

they are different in that adhesion is the force of attraction between the molecules of two different substances, whereas cohesion is the force of attraction between molecules of the same substance.

possible examples include capillary action, in which the adhesion between water and glass causes the water to rise in a narrow tube against the force of gravity.

because of hydrogen bonding, water is extremely cohesive.

this causes molecules on the surface of water to be drawn inward, which is why drops of water form beads on smooth surfaces.

hope this .