You are asked to prepare a solution that is 2% by weight ethanol in water. note that the molecular weight of ethanol is 46.07 g/mol and water is 18.02 g/mol. what is the molality of ethanol in this solution?

0.4429 m

Explanation:

Given that mass % of the ethanol in water = 2%

This means that 2 g of ethanol present in 100 g of ethanol solution.

Molality is defined as the moles of the solute present in 1 kilogram of the solvent.

Given that:

Mass of = 2 g

Molar mass of = 46.07 g/mol

The formula for the calculation of moles is shown below:

Thus,

Mass of water = 100 - 2  g = 98 g = 0.098 kg ( 1 g = 0.001 kg )

So, molality is:

Molality = 0.4429 m