When 0.100 mol of carbon is burned in a closed vessel with8.00
g of oxygen, how many grams of carbon dioxide can form?

Answer : The mass of carbon monoxide form can be 2.8 grams.

Solution : Given,

Moles of C = 0.100 mole

Mass of = 8.00 g

Molar mass of = 32 g/mole

Molar mass of CO = 28 g/mole

First we have to calculate the moles of .

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

From the balanced reaction we conclude that

As, 2 mole of react with 1 mole of

So, 0.1 moles of react with moles of

From this we conclude that, is an excess reagent because the given moles are greater than the required moles and is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of

From the reaction, we conclude that

As, 2 mole of react to give 2 mole of

So, 0.1 moles of react to give 0.1 moles of

Now we have to calculate the mass of

Therefore, the mass of carbon monoxide form can be 2.8 grams.

m=9

step-by-step explanation:

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