Athermopane window consists of two sheets of glass each 10 mm thick, separated by a layer of stagnant air 6 mm thick. find the percentage reduction in heat loss from this pane as compared to that of a single sheet of glass 10 mm thickness. the temperature drop between inside and outside remains same at 25"c. thermal conductivity of glass is 40 times that of air. a) 86.15% b) 96.15% c) 56.15% d) 76.15%

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml

fe 55.85 g/mol and h2o 18.02 g/mol.

football

explanation:

because it is