10 kg of saturated solution of a highly soluble component a at 80°c is cooled to 30°c calculate the amount of an-hydrous crystals are coming out of the solution solubility of a at 80*c is 0.8 kg of a 1 kg of water and at 30°c is 0.3 kg of a 1 kg of water a) 2.73 kg b) 5.73 kg c) 4.73 kg d) 3.73 kg

The amount of anhydrous crystal are coming out of the solution when this is cooled from 80°C to 30°C are 5 kg of A

Explanation:

A saturated solution is a chemical solution containing the maximum concentration of a solute dissolved in the solvent, and knowing the solubility of component A at 80°C it is possible to know their amount, thus:

10Kg of water × = 8 kg of A

The maximum concentration that water can dissolve at 30°C is:

10Kg of water × = 3 kg of A

Thus, the amount of anhydrous crystal are coming out of the solution when this is cooled from 80°C to 30°C are:

8 kg of A - 3 kg of A = 5 kg of A

I hope it helps!

what's the

we can conclude that the melting point of table salt is above room temperature (it's actually 801 deg c). the melting point of mercury must be below room temperature (- 39 deg c).