In solid nacl, the equilibrium separation between neighboring na+ and cl- ions is 0.283 nm. calculate the coulombic energy between na+ and at this distance. give your answer in each of j, ev, and kj/mol units.

Explanation:

It is given that r = 0.283 nm. As 1 nm = .

Hence, 0.283 nm =

where,   e = C

            =

                         =

So,       1 J =

Hence,    U =

                   = 8.9 eV

                = kJ/mol

Therefore, U = kJ/mol

                     =

you need to have a picture of the atom that way we can answer it