Rank the stability of the carbocations from most stable to least stable? 3º carbocation > 20 carbocation > 10 carbocation o all carbocations have the same stability o 1° carbocation > 20 carbocation > 3º carbocation 2° carbocation > 10 carbocation > 3º carbocation

3° carbocation > 2° carbocation > 1° carbocation

Explanation:

Stability of carbocation -

Carbocation , is an electron deficient species , with 6 electrons ,

being an electron deficient species , the carbocation can be stabilized by any group , which gives electron to the carbocation .

hence ,

comparing the case of of a 3° carbocation and a 2° carbocation .

The 3° carbocation , is more stable , due to the presence of three alkyl groups , which donates the electron density to the electron deficient site of the carbocation , hence , is stable ,

but in case of  2° carbocation , there are only two electron donating , alkyl groups , hence , comparing  3° and 2° carbocation , 3° is more stable .

and ,

In case of 1° carbocation , there is only one electron donating , alkyl groups , hence , it is least stable .

Therefore ,

The order of the stability of the carbocation is -

3° carbocation > 2° carbocation > 1° carbocation

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.