5k + kno3 3k2o + n
how much in grams would you need of each reactant to make 27 lbs of nitrogen?

174,957.143 grams of potassium and 89,228.478 grams of potassium nitrate will be needed.

Explanation:

Mass of nitrogen =  27 lbs = 12,247 g

1 lbs = 453.592 g

Moles of nitrogen =

According to reaction, 1 mole of nitrogen is produced from 5 moles of potassium and 1 mole of potassium nitrate.

Then 874.786 mol of nitrogen will be obtained from :

of potassium.

Then 874.786 mol of nitrogen will be obtained from :

of potassium nitrate.

Mass of 4,373.928 moles of potassium:

of potassium

Mass of 874.789 moles of potassium nitrate:

of potassium nitrate

sure what is it? ^w^