the empirical formula of c2h4o2
ch2o
c2h4o2
ch4o
c4h8o4

CH2O

Explanation:

the empirical formula of a compound is determined by obtaining the moles of each element and then divided each element by  the lowest value. represents the simplest ratio in which atoms that form a chemical compound.

for the molecular formula C2H4O2; its empirical formula would be:

moles C: 2/2 = 1

moles H: 4/2 = 2

moles O: 2/2 = 1

⇒ empirical formula: CH2O

b. accuracy of the data matters alot more than its number of digits, organization or amount of detail. quantitative observation is more accepted than the qualitative observation.

answer is: empirical formula is tl₂o. if we use 100 grams of compound, tha:

m(tl) = 96.2%  · 100 g ÷ 100%.

m(tl) = 96.2 g.

n(tl) = m(tl)  ÷ m(tl). n(tl) = 96.2 g  ÷ 204.4 g/mol.

n(tl) = 0.47 mol. m(o) = 3.77 g. n(o) = m(o)  ÷ m(o). n(o) = 3.77 g  ÷ 16 g/mol. n(ag) = 0.235 mol. n(tl) . n(o) = 0.47 mol : 0.235 mol /0.235. n(tl) . n(o) = 2 : 1.

m(tl₂o) = 204.4 g/mol  · 2 + 16 g/mol = 424.8 g/mol.

m(compound) = 456. 8 g/mol - 424.8 g/mol = 32 g/mol ( 2 oxygens); tl₂o₃.