Chemistry, 21.08.2019 05:30 nathanscastr02
Asmall cubical furnace 50 by 50 by 50 cm on the inside is constructed of fireclay brick [k = 1.04 w/m. degree c] with a wall thickness of 10 cm. the inside of the furnace is maintained at 500 degree c, and the outside is maintained at 50 degree c. calculate the heat lost through the walls.
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Be sure to answer all parts. the following equilibrium constants were determined at 1123 k: c(s) + co2(g) â 2co(g) k'p = 1.30 Ă 1014 co(g) + cl2(g) â cocl2(g) k''p = 6.00 Ă 10â3 calculate the equilibrium constant at 1123 k for the reaction: c(s) + co2(g) + 2cl2(g) â 2cocl2(g) 4.68 Ă 10 9 (enter your answer in scientific notation.) write the equilibrium constant expression, kp:
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Asmall cubical furnace 50 by 50 by 50 cm on the inside is constructed of fireclay brick [k = 1.04 w/...
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