Menthol, the substance we can smell in mentholated cough drops, is composed of c, h, and o. a 0.1005 −mg sample of menthol is combusted, producing 0.2829 mg of co2 and 0.1159 mg of h2o. what is the empirical formula for menthol? express your answer as a chemical formula.

The empirical formula for the given compound is  

Explanation:

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of

Mass of

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 0.0002829 g of carbon dioxide, of carbon will be contained.

For calculating the mass of hydrogen:

In 18 g of water, 2 g of hydrogen is contained.

So, in 0.0001159 g of water, of hydrogen will be contained.

Mass of oxygen in the compound = (0.0001005) - (0.00007715 + 0.00001288) = 0.00001047 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon =

Moles of Hydrogen =

Moles of Oxygen =

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is .

For Carbon =

For Hydrogen  =

For Oxygen  =

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 10 : 20 : 1

Hence, the empirical formula for the given compound is  

indium, and thallium have three electrons i think

a:

by the combination of an unlimited number of elements