At a particular temperature, k 5.0 x 10-6 for the reaction 2co2(9) 2co(9) +02(9) if 3.0 moles of co2 is initially placed into a 5.0-l vessel, calculate the equilibrium concentrations of all species. co2] co] o2l [02]-

Answer : The concentration of at equilibrium will be, 0.598 M, 0.00216 M and 0.00108 M respectively.

Explanation : Given,

Equilibrium constant =

tex]\text{Concentration of }CO_2=\frac{\text{Moles of }CO_2}{\text{Volume of solution}}=\frac{3.0mole}{5.0L}=0.6mole=0.6M[/tex]

The balanced equilibrium reaction is,

Initial conc.     0.6 M                 0             0

At eqm.        (0.6-2x) M          2x M         x M

The expression of equilibrium constant for the reaction will be:

Now put all the values in this expression, we get :

By solving the term 'x', we get:

Concentration of at equilibrium =

Concentration of at equilibrium =

Concentration of at equilibrium =

calculate how many grams of ammonia can be produced from 4.21 grams of

n2 + 3h2 = 2nh3

my answer:

25.0g n2 x (1 mol/ 28.0gn2) x (2 mol nh3/ 1 mol n2) x (17.0g nh3/ 1 molnh3) = 30.36g n2

25.0g h2 x (1 mol h2/ 2.00g h2) x (2 mol nh3/ 3 mol h2) x (17.0g nh3/ 1 mol nh3) = 141.67g h2

lr = n2

explanation:

i think option no d is the correct answer