Sulfuric acid (h2so4) reacts with potassium hydroxide (koh) as follows. h2so4(aq) + 2 koh(aq) k2so4(aq) + 2 h2o(l) calculate the volume of 0.100 m sulfuric acid required to neutralize 25.0 ml of 0.0821 m koh.

The volume of comes out to be 10.2625 mL.

Explanation:

To calculate the concentration of acid, we use the equation given by neutralization reaction:

where,

are the n-factor, molarity and volume of acid which is

are the n-factor, molarity and volume of base which is KOH.

We are given:

Putting values in above equation, we get:

Hence, the volume of comes out to be 10.2625 mL.

what are the two models

explanation: