According to this chemical reaction, which is the number of grams of fe produced from 14 moles of h2? fe3o4 + 4 h2 → 3 fe + 4 h2o

From the equation of the reaction,  the mass of Fe produced from 14 moles of H₂ is 588 g.

The equation of the reaction is given as follows:

From the equation of the reaction, 4 moles of H₂ produces 3 moles of Fe.

14 moles of H₂ will produce 14 * 3/4 moles of Fe = 10.5 moles of Fe.

Mass of 10.5 moles of Fe = 56 * 10.5

Mass of 10.5 moles of Fe = 588 g

Therefore, the mass of Fe produced from 14 moles of H₂ is 588 g.

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Explanation:

We know we will need a balanced equation with masses, moles, and molar masses, so let’s gather all the information in one place.

M_r:                            55.85  

            Fe₃O₄ + 4H₂ → 3Fe + 4H₂O

n/mol:                  14

1. Use the molar ratio of Fe:H₂ to calculate the moles of Fe.

2. Use the molar mass of Fe to calculate the mass of Fe

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