The vapor pressure of water is 23.76 mm hg at 25 °c. a nonvolatile, nonelectrolyte that dissolves in water is sucrose. calculate the vapor pressure of the solution at 25 °c when 12.25 grams of sucrose, c12h22o11 (342.3 g/mol), are dissolved in 176.3 grams of water. water = h2o = 18.02 g/mol.

Answer : The vapor pressure of solution is 23.67 mmHg.

Solution:

As the relative lowering of vapor pressure is directly proportional to the amount of dissolved solute.

The formula for relative lowering of vapor pressure will be,

where,

= vapor pressure of pure solvent  (water) = 23.76 mmHg

= vapor pressure of solution= ?

= mass of solute  (sucrose) = 12.25 g

= mass of solvent  (water) = 176.3 g

= molar mass of solvent (water) = 18.02 g/mole

= molar mass of solute (sucrose) = 342.3 g/mole

Now put all the given values in this formula ,we get the vapor pressure of the solution.

Therefore, the vapor pressure of solution is 23.67 mmHg.