A51.24-g sample of ba(oh)2 is dissolved in enough water to make 1.20 l of solution. how many milliliters of this solution must be diluted with water in order to make 1.00 l of 0.100 m ba(oh)2?

361.5 ml of water will required to make 1.00 L of 0.100 M .

Explanation:

Mass of barium hydroxide = 51.24 g

Volume of solution = 1.20 L

Molarity of the solution =

Let the volume of the solution 0.2766 M to be diluted be

Desired concentration of barium hydroxide solution =

Volume of the 0.1000 M solution =

361.5 ml of water will required to make 1.00 L of 0.100 M .

the answer to this question is 3.

the electron configuration that you gave me has 16 electrons ergo it has 16 protons ergo it is the element sulfur.