The field from a large plate a is 1180 n/c pointing eastward, while another plate b produces a field that is 1520 n/c northward. what is the net field produced by the combination?
? n/c
an object has been charged to 480 μc and placed in the field.
what is the magnitude of the force on the object?
? n

E=1924.26 N/C

F=0.92 N

Explanation:

As we know that electric field is a vector quantity.It means that it have direction.

Plate A

E(A) = 1180 N/C  ,Eastward

Plate B

E(B) =1520 N/C ,Northward

The resultant electric field given as

E=1924.26 N/C

We know that

F = q E

Here q =480 μC

E=1924.26 N/C

By putting the values

F = q E

F=0.92 N

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