You place a balloon in a closed chamber at stp. you increase the chamber pressure by a factor of 10. what happens to the balloon?

Answer : The temperature of balloon increases to 10 times of original temperature.

Explanation :

In this problem, volume remain constant. The temperature and pressure will vary.

Gay-Lussac's Law : It is defined as the pressure of the gas is directly proportional to the temperature of the gas at constant volume and number of moles.

or,

where,

= let initial pressure = x

= final pressure = 10x

= initial temperature

= final temperature

Now put all the given values in the above equation, we get:

From this we conclude that, the temperature increases to 10 times of original temperature.

Hence, the temperature of balloon increases to 10 times of original temperature.

what is the volume occupied by 40 grams of argon gas (ar) at standard conditions? what volume, in liters, is occupied by 1.5 x 1023 

warm front forms when a moist, warm air mass slides up and over a cold air mass. as the warm air mass rises, it condenses into a broad area of clouds. a warm front brings gentle rain or light snow, followed by warmer, milder weather.

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