Adog and a cat are 200 meters apart when they see each other. the dog can run at a speed of 30 m/sec, while the cat can run at a speed of 24 m/sec.
a
how soon will they meet if they simultaneously start running towards each other?

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The dog will catch the cat at  33.33 sec

Step-by-step explanation:

Let

x> distance the cat runs before being caught by the dog,

Remember that

The speed is equal to divide the distance by the time

v=d/t

solve for t

t=d/v

so

equate the time

x/24=(200+x)/30

30x=24(200+x)

30x=4,800+24x

30x-24x=4,800

x=4,800/6=800 m

t=d/v=800/24=33.33 sec

or

t=(800+200)/30=1,000/30=33.33 sec

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step-by-step explanation:

sorry man i accidentally pressed yes my bad

step-by-step explanation: