Hydrogen and oxygen react under a specific set of conditions to produce water according to the equation:
2h2(g)+o2(g) -> 2h2o(g)
how much hydrogen would be required to produce 5.5 mol of water?

and how much oxygen would be required?

1. The amount required of H₂ = 11.0 g.

2. The amount required of O₂ = 88.0 g.

Explanation:

2H₂(g) + O₂(g) → 2H₂O,

It is clear that 2.0 moles of H₂ react with 1.0 mole of O₂ to produce 2.0 moles of H₂O.

Q1: How much hydrogen would be required to produce 5.5 mol of water?

Using cross multiplication:

2.0 mol of H₂ produce → 2.0 mol of H₂O, from stichiometry.

??? mol of H₂ produce → 5.5 mol of H₂O.

∴ the no. of moles of H₂ needed to produce 5.5 mol of water = (2.0 mol)(5.5 mol)/(2.0 mol) = 5.5 mol.

mass of H₂ = (no. of moles)(molar mass) = (5.5 mol)(2.0 g/mol) = 11.0 g.

Q2: How much oxygen would be required?

Using cross multiplication:

1.0 mol of O₂ produce → 2.0 mol of H₂O, from stichiometry.

??? mol of O₂ produce → 5.5 mol of H₂O.

∴ the no. of moles of O₂ needed to produce 5.5 mol of water = (1.0 mol)(5.5 mol)/(2.0 mol) = 2.75 mol.

mass of O₂ = (no. of moles)(molar mass) = (2.75 mol)(32.0 g/mol) = 88.0 g.

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