Chemistry, 05.02.2020 08:45 cuppykittyy

When 2.50grams of nacl is dissolved in 2liters of water what is the concentration of the solutuon

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Answer from: wowlol448

The concentration of the solution is also known as Molarity (M). The formula for molarity is

M = mol / liters

We already have the liters, so we only need to find moles. We can find the number of moles by using the molar mass of NaCl and the given amount. That can be found using the elements' atomic weights given on the periodic table.

22.990 (mass of Na) + 35.453 (mass of Chlorine) = 58.443 g / mol

That's how many grams are in one mole of NaCl, but we only have 2.5 grams. So, let's divide and see how many moles we have.

2.5 / 58.443 = .042776 moles

Now we can plug our numbers into the formula.

$M = \frac{mol}{liters}$

$M = \frac{.042776 mols}{2 liters}$

M = .02138 mols/L

So, your concentration is about .02 mol/L.

Answer from: Quest

am i too late?

explanation:

Answer from: Quest

assuming that your periodic table has eighteen columns, you should highlight the four elements in the third column from the left of the table.

explanation

neutral atoms of elements after calcium contain d electrons. the energy of d orbitals of a particular main shell lies between the energy of the s and p orbitals of the next main shell. for example, electrons in the $3d$ have energy higher than those in the $4 s$ orbital while lower than those of the $4 p$ orbital.

by the aufbau principle, electrons fill orbitals one at a time, starting from those of the lowest energy. the $4s$ orbital is therefore filled right after $3p$ orbitals and before $3 d$ orbitals.

potassium has electron configuration $[\text{ar}] 4 s^{1}$ and calcium $[\text{ar}] 4 s^{2}$ . the s orbital of a main shell holds a maximum of two electrons. the next element would thus have the electron configuration $[\text{ar}] 4 s^{2} \; 3d^{1}$ and satisfy the requirements.

a neutral atom of the element contains three electrons on top of the most recent noble gas element. it should thus be placed in the third column of the periodic table. both scandium and yttrium would satisfy the conditions. an aufbau diagram indicates that the 4f orbital is filled before the 5d. however, it appears that exceptions exists for both lanthanum and actinium. neutral atoms of the two d-block elements also demonstrate the $ns^{2} \; (n-1) p^{1}$ and should be highlighted as well.

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