Calculate the moles of 12.354 grams of c6h12o6

The correct answer is 0.06857 moles.

C₆H₁₂O₆, that is, glucose has six carbons, twelve hydrogens, and six oxygen atoms. The atomic weight of C, H and O are as follows:

Six atoms of carbon = 6 × 12.01 g = 72.06 g

Twelve atoms of hydrogen = 12 × 1.008 g = 12.096 g

Six atoms of oxygen = 6 × 16.00 g = 96.00 g

So, the molar mass of C₆H₁₂O₆ is 72.06 g + 12.096 g + 96.0 g = 180.156 g.

It can also be written in the form as 180.16 g of C₆H₁₂O₆ is equal to 1 mole of C₆H₁₂O₆or 180.16 g/mole (as the molar mass)

Now, there is a need to find moles of 12.354 grams of C₆H₁₂O₆. So, the final conversion is:

12.354 g C₆H₁₂O₆ × 1 mole of C₆H₁₂O₆ / 180.16 g C₆H₁₂O₆

= 0.06857 moles

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