Use the periodic table to determine the electron configuration for iodine (i). express your answer in noble gas condensed form.

The atomic number for iodine (I) = 53

The electron for I is:

1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁵

Now, among the noble gases, Krypton (Kr) has an atomic number 36. Thus we can write:

I = [1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ ] 5s² 4d¹⁰ 5p⁵

I = [Kr] 5s² 4d¹⁰ 5p⁵

(or)

I = [Kr]  4d¹⁰ 5s² 5p⁵

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