How many particles are present in 15.0 g of ccl4? (show work : ))

5.86*10^22particles

Explanation:

First obtain the molar mass of tetrachloromethane then compare the given mass in the question with Avogadro's number as shown in the solution. Note that the Avogadro's number is the number of particles contained by one mole of all substances at standard temperature and pressure. According to Avogadro, at the same temperature and pressure, one mole of all substances contain equal number of molecules

a:

by the combination of an unlimited number of elements

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :