The half-life of cesium-137 is 30 years. suppose we have a 200-mg sample. (a) find the mass that remains after t years.

Given:

Half life(t^ 1/2) :30 years

A0( initial mass of the substance): 200 mg.

Now we know that

A= A0/ [2 ^ (t/√t)]

Where A is the mass that remains after t years.

A0 is the initial mass

t is the time

t^1/2 is the half life

Substituting the given values in the above equation we get

A= [200/ 2^(t/30) ] mg

Thus the mass remaining after t years is [200/ 2^(t/30) ] mg

3 hours because it is a decent distance.

it forms an anion that has a larger radius. anions have a negative charge and are larger than the original atom.