Let V be the volume of the pyramid of height 11 whose base is a square of side length 6. Find a formula for the area A of the horizontal cross section at a height y.

Base area = 36

Volume of the pyramid = 132

Step-by-step explanation:

Volume of a pyramid = Base Area × Height/3

Base area = Length × Length (since base of the pyramid is a square)

Given the side length of the square = 6

Base area = 6×6

Base area = 36

Given height of pyramid =11

Volume of the pyramid = 36×11/3

Volume of the pyramid = 12×11

Volume of the pyramid = 132

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step-by-step explanation:

∆abc has the points a(1, 7), b(-2, 2), and c(4, 2) as its vertices. formed with the point d(1, 2) as its third vertex, then ∆abd is triangle.