When 108 g of water at a temperature of 23.9 °c is mixed with 66.9 g of water at an unknown temperature, the final temperature of the resulting mixture is 47.2 °c. what was the initial temperature of the second sample of water? (the specific heat capacity of liquid water is 4.184 j/g ⋅

Here,

Heat gain by the first sample of water + Heat lost by the second sample of water is equal to zero (0).

Now, Mass of water sample one = 108 g (given)

Mass of water sample two = 66.9 g (given)

Temperature for water sample one =

Let, temperature for water sample two =x

And, final temperature =

Now,

where, = final temperature

= initial temperature

Substitute all the given values in above formula:

[tex x =84.81^{0}C [/tex]

d.) circle motion requires a force to give it a centripetal acceleration.