Calculate the mass percent of a nacl solution in which 199 g of nacl is dissolved in 2.74 l of water at 25 ∘c (density = 0.997 g/ml).

Hey there!

mass of solvent :

volume in mL => 2.74 * 1000 => 2740 mL

D = m / V

0.997 = m / 2740

m = 0.997 * 2740

m = 2731.78 g of solvent

Therefore :

T % = ( mass solute / mass solute + mass solvent ) * 100

T% = ( 199 / 199 + 2731.78 ) * 100

T% = ( 199 / 2930.78 ) * 100

T% = 0.0679 * 100

T = 6.79 % of NaCl

hope this helps!

answer: -

reaction:

na + cl ⇌ nacl

balanced chemical equation:

na + 2cl ⇌ nacl2

sodium + clorine goes to form sodium chloride (table salt).

the product is nacl2.

and the reactants are na and cl.

(note: if you don’t know what ⇌ means, read below: -

⇌(double head arrow) means reversible reaction).