How many electrons are necessary to produce a charge of -0.90 c ?

One electron has a charge of -1.6* 10^-19 c

x electrons have a charge of -0.90 c

1/x = -1.6 * 10^-19 c / - 0.9 c cancel the c's. and the - signs.

1/x = 1.6 * 10^-19 / 0.9 Cross multiply

0.9 = 1.6 * 10^-19 x Divide by 1.6 * 10^-19

0.9 / 1.6 * 10^-19 = x

x = 5.625 * 10^18 electrons.

it would be b. 6co2 + 6h2o --> c6h12o6 + 6o2

here are some of the ways in which chemical and nuclear reactions differ.

explanation: