What is the mass of silver metal produced from 6.35 g of copper? __cu(s) + __agno3 (aq) → __cu(no3)2 (aq) + __ag(s)?

The mass of silver metal produced from 6.35g of copper is 21.574 grams

calculation

Cu + 2AgNO3 → Cu(NO3)2 +2 Ag

find the moles of Cu used = mass/molar mass of Cu

moles = 6.35/63.5 =0.1 Moles

by use of mole ratio between Cu to Ag which is 1:2 the moles of Ag is therefore= 0.1 x2= 0.2 moles

mass of Ag = moles x molar mass

= 0.2 moles x 107.87 g/mol = 21.574 grams

i would say b

explanation:

but i think i would need more information than that

in the analysis of systems that involve fluid flow, we frequently encounter the combination of properties u and pv.