The equation below shows the decomposition of lead nitrate. how many grams of oxygen are produced when 4.60 g no is formed? pb(no3)2 (s) → pbo (s) + no2 (g) + o2 (g) show all the work

            0.8 g of O₂

Solution:

             The balance chemical equation is as follow,

                         2 Pb(NO₃)₂      →     2 PbO + 4 NO₂ + O₂

According to equation,

     184 g (4 moles) NO₂ is produced along with  =  32 g (1 mole) O₂ gas

So,

    4.60 g NO₂ when formed will produce along  =  X g of O₂

Solving for X,

                     X  =  (32 g × 4.60 g) ÷ 184 g

                     X  =  0.8 g of O₂

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