Red -green color blindness is an x linked recessive disorder . since normal vision is dominant, it is typically represented as x8. if a normal female wants to have children with a color blind now what is the probability of having a son who is colorblind? a daughter who is colorblind? a daughter who is a carrier ? in addition determine the genotypes of the two parents.

          x         y

x8     x8x     x8y

x8      x8x     x8y

The results of the punnet square show that:

They will not have a son who will be colour blind.

They will not have a daughter who is colour blind.

All the daughters born will be carriers of red- green colour blindness.

The genotype of the two parents will be:

Genotype of mother: x8,x8

Genotype of father: x, Y

the answer would be 2, if crossing over doesn’t occur 2 out of 4 of the daughter cells will have that allele.

hope this : )

c is the answer. hope this