1415*98+6+7655 a machine produces metal rods used in an automobile suspension system. a random sample of 15 rods is selected and the diameter is measured. the resulting data (in millimeters) are as follows: no. 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 dia. 8.21 8.19 8.23 8.25 8.26 8.23 8.20 8.26 8.19 8.23 8.20 8.28 8.24 8.25 8.24 use the data above to calculate a 95% two-sided confidence interval on the mean rod diameter. assume the data are normally distributed. (a) calculate the sample mean and standard deviation. round the sample mean and the sample standard deviation to 2 and 3 decimal places respectively (e. g. 98.76 and 98.765).

1415*98+6+7655 A machine produces metal rods used in an automobile suspension system. a random sample of 15 rods is selected and the diameter is measured. the resulting data (in millimeters) are as follows: no. 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 dia. 8.21 8.19 8.23 8.25 8.26 8.23 8.20 8.26 8.19 8.23 8.20 8.28 8.24 8.25 8.24 use the data above to calculate a 95% two-sided confidence interval on the mean rod diameter. assume the data are normally distributed. (a) calculate the sample mean and standard deviation. round the sample mean and the sample standard deviation to 2 and 3 decimal places respectively (e.g. 98.76 and 98.765).

1415*98+6+7655 A machine produces metal rods used in an automobile suspension system. a random sample of 15 rods is selected and the diameter is measured. the resulting data (in millimeters) are as follows: no. 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 dia. 8.21 8.19 8.23 8.25 8.26 8.23 8.20 8.26 8.19 8.23 8.20 8.28 8.24 8.25 8.24 use the data above to calculate a 95% two-sided confidence interval on the mean rod diameter. assume the data are normally distributed. (a) calculate the sample mean and standard deviation. round the sample mean and the sample standard deviation to 2 and 3 decimal places respectively (e.g. 98.76 and 98.765).

i think it's b, lmk if it was