The sum of two numbers is 15 the numbers are such that one third of the larger is equal to half the smaller find the numbers​ MATHEMATICS QUESTION NOT SPANISH...SORRY

The numbers are:

9 and 6

Explanation:

a+b = 15   (eq. 1)

a/3 = b/2  (eq. 2)

from eq. 2:

a = 3b/2   (eq. 3)

Substituting the value of the eq. 3 into the eq. 1:

3b/2 + b = 15

3b/2 + 2b/2 = 15

(3b + 2b)/2 = 15

3b + 2b = 15*2

5b = 30

b = 30/5

b = 6

from eq. 1:

a + 6 = 15

a = 15 - 6

a = 9

Check:

from eq. 2:

9/3 = 6/2 = 3

6 and 9

Explanation:

X + y = 15

X/3 = y/2 2x = 3y 2x - 3y = 0

3(x+y)=(3)(15)

(3x+3y=45) +( 2x - 3y=0). 3y-3y=0

3x + 2x = 45

X = 45/5

X = 9

15-9 =6

Y = 6

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