By step process. For an example, se pus The length of the floor is 32 m longer than its width and there is greater than 200
square meters. You will cover the floor completely with tiles. What will be the
possible dimension of the floor?

Length = width + 32, where width > 5.36

Explanation:

Let,

width of the floor be = x

length of the floor = x + 32

area of the floor > 200 m²

From the statement of the problem;

x(x + 32)  > 200

x² + 32x - 200 > 0

Solving the quadratic by formula method;

x = (-b +√ b² - 4ac) / 2a

Note;

a = 1

b= 32

c= -200

x = -32 ±√32² - (4 • 1 • (-200)) / (2) (1)

x =  -32 ±√1024 + 800) / 2

x =-32 ±42.71/2

So the roots are,

x1 = - 37.4

x2 = 5.36

But length can not be negative hence; x = 5.36

Substituting values;

width = 5.36

length = 5.36 + 32 = 37.36

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