The Jones family was one of the first to come to the U. S. They had 4 children. Assuming that the probability of a child being a girl is .5, find the probability that the Jones family had:.
(a) at least 3 girls
(b) at most 3 girls

a) The probability that the Jones family had at least 3 girls is 0.3125.

b) The probability that the Jones family had at most 3 girls is 0.9375.

Explanation:

The probability that the Jones family had at least 3 girls is obtained below:

From the given information, let X be the number of girls follows binomial distribution with number of trails 4 and probability of success is 0.5. Jones having four children. The 0.5 probability that having girl.That is,  and p=0.50The probability mass function of X is ; P (X = x) = 4Cx X (0.5)^x X  (1 - 0.5)^4-x

a) P(At least 3 girls) = P(3 girls) + P(4 girls)

= 4C3 x (0.5)^3 x (0.5)^1 + (0.5)^4

= 0.3125 is the probability that the Jones family had at least 3 girls

b) at most 3 girls ; The probability that the Jones family had at most 3 girls is obtained below:

From the given information, let X be the number of girls follows binomial distribution with number of trails 4 and probability of success is 0.5.  and .The probability mass function of X is, P (X = x) = 4Cx X (0.5)^x X  (1 - 0.5)^4-xThe required probability is P(x<=3) = 1 - P(X>3) = 1 - P(X = 4)= 1 - 0.0625

The probability that the Jones family had at most 3 girls is 0.9375.

Don jorge (1) se levantaba a las seis de la mañana. vivía cerca del ayuntamiento, pero le gustaba llegar temprano. (2) salir de su casa, tomaba un desayuno bien completo: café con leche, tostadas, queso y fruta. ya en el ayuntamiento, (3) se reunía con su secretario para ver la agenda del día. (4) ver la agenda, se tomaba un café. él siempre se tomaba un café (5) leía la prensa del día. (6) , don jorge recibía a los ciudadanos que querían hablar con él.