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When water is boiled under a pressure of 2.00 atm, the heat of vaporization is 2.20 10^6 j/kg and the boiling point is 120 c. at this pressure, 1.00 kg of water has a volume of 1.00 10^- 3 m^3, and 1.00 kg of steam has a volume of 0.824 m^3. compute the work done when 1.00 kg of steam is formed at this temperature.

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When water is boiled under a pressure of 2.00 atm, the heat of vaporization is 2.20 10^6 j/kg and th...
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